Given an integer array nums
, find the sum of the elements between indices i
and j
(i ≤ j
), inclusive.
Example:
Given nums = [-2, 0, 3, -5, 2, -1]
sumRange(0, 2) -> 1
sumRange(2, 5) -> -1
sumRange(0, 5) -> -3
Note:
- You may assume that the array does not change.
- There are many calls to sumRange function.
令状态f[i]
为0到i
元素之间的和,则状态转移方程为 f[i] = f[i-1] + nums[i]
。f[i]
本质上是累加和,有了f[i]
,则范围[i,j]之间的和等于f[j] - f[i-1]
。
{% if book.java %} {% codesnippet "./code/range-sum-query-immutable."+book.suffix, language=book.suffix %}{% endcodesnippet %} {% endif %}