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__in__ appears always returns False #24

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talwrii opened this issue Apr 4, 2023 · 0 comments
Open

__in__ appears always returns False #24

talwrii opened this issue Apr 4, 2023 · 0 comments

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@talwrii
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talwrii commented Apr 4, 2023

It should error out or return the correct result.

(Pdb) self.store["blah"] = "1"
(Pdb) "blah" in self.store
False
(Pdb) self.store["blah"]
b'1'
(Pdb) self.store
<semidbm.db._SemiDBM object at 0x11f6ec050>
(Pdb) semidbm.__version__
'0.5.1'
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