@author jackzhenguo @desc @date 2019/11/23 126 斐波那契数列前n项 def fibonacci(n): a, b = 1, 1 for _ in range(n): yield a a, b = b, a + b list(fibonacci(5)) # [1, 1, 2, 3, 5] [上一个例子](125.md) [下一个例子](127.md)