Skip to content
New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Problem 2.5 a #5

Open
nbraynor opened this issue Dec 28, 2020 · 4 comments
Open

Problem 2.5 a #5

nbraynor opened this issue Dec 28, 2020 · 4 comments

Comments

@nbraynor
Copy link

Perhaps you can help me with my confusion about this problem. It appears in the r2-2r1 step, your solution accidentally performed -A24-2A14 to get a value of -3 for A24 instead of A24-2A14 to get a 7 for A24. I don't think the correct solution is not an empty solution set. There are four equations and four unknowns and the solution is [x1 x2 x3 x4]T = [26/15 -13/30 2/5 -1/10]T. Am I thinking about this the wrong way?

@sangyun884
Copy link

I think so. A24 is 7 after subtraction

@malshoff
Copy link

No, his answer is correct. (-)2/1 = -2, so you multiply row 1 by -2 and add that to row 2. Same thing for row 3, and for row four, you'll multiply row 1 by (-5)/1 = -5, and add that to row 4. It's step 7 listed here: https://www.statlect.com/matrix-algebra/Gaussian-elimination

@raphsimon
Copy link

His answer is not correct since he doesn't even start off with the right matrix. R2 is [2 5 -7 -5 | -2] and not [2 5 -7 5| -2]. System 2.5 a does not have a solution.

@Tianmaru
Copy link

Tianmaru commented Oct 4, 2024

His answer is not correct since he doesn't even start off with the right matrix. R2 is [2 5 -7 -5 | -2] and not [2 5 -7 5| -2]. System 2.5 a does not have a solution.

Thank you, I came to the same conclusion.

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
Labels
None yet
Projects
None yet
Development

No branches or pull requests

5 participants