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UHF in xtb #792

Answered by cplett
WentongZhou asked this question in Q&A
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Hi,
Indeed, uhf is the number of unpaired electrons so defining --uhf 0 is correct in this case.
If the two molecules come quite close (which I would expect due to the positive charge of the CH3 fragment), the electrostatic energy can become really high due to the electron/electron repulsion and is compensated by the charge transfer term. Therefore, the result seems reasonable.

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Answer selected by marcelmbn
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Converted from issue

This discussion was converted from issue #790 on March 24, 2023 08:28.