Code - sum of digits of a number

Author: sarayusreeyadavpadala

Sum of digits of a number.py

@@ -1,13 +1,33 @@
-q=0   # Initially we assigned 0 to "q", to use this variable for the summation purpose below.
-    # The "q" value should be declared before using it(mandatory). And this value can be changed later.
+# Python code to calculate the sum of digits of a number, by taking number input from user.
 
-n=int(input("Enter Number: "))   # asking user for input
-while n>0:         # Until "n" is greater than 0, execute the loop. This means that until all the digits of "n" got extracted.
+import sys
 
-   r=n%10           # Here, we are extracting each digit from "n" starting from one's place to ten's and hundred's... so on.
+def get_integer():
+    for i in range(3,0,-1):                       # executes the loop 3 times. Giving 3 chances to the user.
+        num = input("enter a number:")
+        if num.isnumeric():                       # checks if entered input is an integer string or not.
+            num = int(num)                        # converting integer string to integer. And returns it to where function is called.
+            return num
+        else:
+            print("enter integer only")                    
+            print(f'{i-1} chances are left' if (i-1)>1 else f'{i-1} chance is left')     # prints if user entered wrong input and chances left.
+        continue   
+        
 
-   q=q+r            # Each extracted number is being added to "q".
+def addition(num):
+    Sum=0
+    if type(num) is type(None):               # Checks if number type is none or not. If type is none program exits.
+        print("Try again!")
+        sys.exit()
+    while num > 0:                            # Addition- adding the digits in the number.
+        digit = int(num % 10)
+        Sum += digit
+        num /= 10
+    return Sum                                # Returns sum to where the function is called.
 
-   n=n//10          # "n" value is being changed in every iteration. Dividing with 10 gives exact digits in that number, reducing one digit in every iteration from one's place.
 
-print("Sum of digits is: "+str(q))
+
+if __name__ == '__main__':                    # this is used to overcome the problems while importing this file.                         
+    number = get_integer()
+    Sum = addition(number)
+    print(f'Sum of digits of {number} is {Sum}')      # Prints the sum