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155.min-stack.go
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/*
* @lc app=leetcode id=155 lang=golang
*
* [155] Min Stack
*
* https://leetcode.com/problems/min-stack/description/
*
* algorithms
* Easy (36.85%)
* Likes: 1731
* Dislikes: 179
* Total Accepted: 296.9K
* Total Submissions: 805.6K
* Testcase Example: '["MinStack","push","push","push","getMin","pop","top","getMin"]\n[[],[-2],[0],[-3],[],[],[],[]]'
*
*
* Design a stack that supports push, pop, top, and retrieving the minimum
* element in constant time.
*
*
* push(x) -- Push element x onto stack.
*
*
* pop() -- Removes the element on top of the stack.
*
*
* top() -- Get the top element.
*
*
* getMin() -- Retrieve the minimum element in the stack.
*
*
*
*
* Example:
*
* MinStack minStack = new MinStack();
* minStack.push(-2);
* minStack.push(0);
* minStack.push(-3);
* minStack.getMin(); --> Returns -3.
* minStack.pop();
* minStack.top(); --> Returns 0.
* minStack.getMin(); --> Returns -2.
*
*
*/
type MinStack struct {
s1 []int
s2 []int
}
/** initialize your data structure here. */
func Constructor() MinStack {
return MinStack{
s1: []int{},
s2: []int{},
}
}
func (this *MinStack) Push(x int) {
this.s1 = append(this.s1, x)
if len(this.s2) == 0 || this.s2[len(this.s2)-1] >= x {
this.s2 = append(this.s2, x)
}
}
func (this *MinStack) Pop() {
if len(this.s1) > 0 {
pop := this.s1[len(this.s1)-1]
this.s1 = this.s1[:len(this.s1)-1]
if pop == this.s2[len(this.s2)-1] {
this.s2 = this.s2[:len(this.s2)-1]
}
}
}
func (this *MinStack) Top() int {
if len(this.s1) > 0 {
return this.s1[len(this.s1)-1]
}
return -1
}
func (this *MinStack) GetMin() int {
if len(this.s2) > 0 {
return this.s2[len(this.s2)-1]
}
return -1
}
/**
* Your MinStack object will be instantiated and called as such:
* obj := Constructor();
* obj.Push(x);
* obj.Pop();
* param_3 := obj.Top();
* param_4 := obj.GetMin();
*/