Docs can be previewed here: https://github.com/formal-methods-mpi/Taxonomy.jl/previews/PR106

Simple draft for extracting Structurals from LatentPathmodels and sample randomly. Also renamed structural_model - Argument, see b083ce7. Closes #98

I ran into a question concerning the resulting type of the sampled StenoGraph-Vector:

using StenoGraphs

graph_1 = StenoGraphs.@StenoGraph begin
    # latent regressions
    fac1 → fac2
end

struct NodeLabel_2 <: NodeModifier
    l
end
graph_2 = StenoGraphs.@StenoGraph begin
    # latent regressions
    fac1 → fac2^NodeLabel_2("Home an der Spree")
end

# These two graphs have slightly different types:
typeof(graph_1)
typeof(graph_2)

# When putting them into a vector, the Vector gets the type `Vector{Vector}`:
[graph_1, graph_2]

I would think, something like Vector{AbstractEdge} would be more appropriate? However, i'm not quite sure how to achive that. I played around with convert() a bit, but wasn't successfull.

Can you open this as an issue in StenoGraphs?

Simple draft for extracting Structurals from LatentPathmodels and sample randomly. Also renamed structural_model - Argument, see b083ce7. Closes #98
I ran into a question concerning the resulting type of the sampled StenoGraph-Vector:

using StenoGraphs

graph_1 = StenoGraphs.@StenoGraph begin
    # latent regressions
    fac1 → fac2
end

struct NodeLabel_2 <: NodeModifier
    l
end
graph_2 = StenoGraphs.@StenoGraph begin
    # latent regressions
    fac1 → fac2^NodeLabel_2("Home an der Spree")
end

# These two graphs have slightly different types:
typeof(graph_1)
typeof(graph_2)

# When putting them into a vector, the Vector gets the type `Vector{Vector}`:
[graph_1, graph_2]

I would think, something like Vector{AbstractEdge} would be more appropriate? However, i'm not quite sure how to achive that. I played around with convert() a bit, but wasn't successfull.

Can you open this as an issue in StenoGraphs?

Done: aaronpeikert/StenoGraphs.jl#56