-
Notifications
You must be signed in to change notification settings - Fork 0
/
200.number-of-islands.cpp
85 lines (84 loc) · 1.85 KB
/
200.number-of-islands.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
/*
* @lc app=leetcode id=200 lang=cpp
*
* [200] Number of Islands
*
* https://leetcode.com/problems/number-of-islands/description/
*
* algorithms
* Medium (40.25%)
* Total Accepted: 303.2K
* Total Submissions: 753.5K
* Testcase Example: '[["1","1","1","1","0"],["1","1","0","1","0"],["1","1","0","0","0"],["0","0","0","0","0"]]'
*
* Given a 2d grid map of '1's (land) and '0's (water), count the number of
* islands. An island is surrounded by water and is formed by connecting
* adjacent lands horizontally or vertically. You may assume all four edges of
* the grid are all surrounded by water.
*
* Example 1:
*
*
* Input:
* 11110
* 11010
* 11000
* 00000
*
* Output: 1
*
*
* Example 2:
*
*
* Input:
* 11000
* 11000
* 00100
* 00011
*
* Output: 3
*
*/
#include <vector>
#include <set>
#include <utility>
using namespace std;
class Solution
{
public:
int numIslands(vector<vector<char>> &grid)
{
int count = 0;
set<pair<int, pair<int, int>>> v;
for (int i = 0, h = grid.size(); i < h; i++)
{
for (int j = 0, w = grid[i].size(); j < w; j++)
{
if (grid[i][j] != '0')
{
if (v.find(pair(i, pair(i, j))) == v.end())
count++;
visitIsland(v, grid, i, j, h, w);
}
}
}
return count;
}
void visitIsland(set<pair<int, pair<int, int>>> &v,
vector<vector<char>> &grid, int row, int col, int h, int w)
{
if (v.find(pair(row, pair(row, col))) == v.end() && grid[row][col] == '1')
{
v.insert(pair(row, pair(row, col)));
if (row - 1 >= 0)
visitIsland(v, grid, row - 1, col, h, w);
if (row + 1 < h)
visitIsland(v, grid, row + 1, col, h, w);
if (col - 1 >= 0)
visitIsland(v, grid, row, col - 1, h, w);
if (col + 1 < w)
visitIsland(v, grid, row, col + 1, h, w);
}
}
};