function inline with simple async code

[stephane-archer]

function inline with simple async code

Future<void> foo(int i, int j) async{
  await Future.delayed(const Duration(seconds: 1));
  print(i);
  print(j);
}

Future<void> main() async {
  int i = 1;
  int j = 1;
  await foo(i, j);
}

inline foo result:

Future<void> main() async {
  int i = 1;
  int j = 1;
  await (int i, int j) async{
    await Future.delayed(const Duration(seconds: 1));
    print(i);
    print(j);
  }(i, j);
}

expected code:

Future<void> main() async {
  int i = 1;
  int j = 1;
  await Future.delayed(const Duration(seconds: 1));
  print(i);
  print(j);
}

this pattern is valid but unnecessary it creates a lambda rather than inlining
await (int i, int j) async{ ................ }(i, j);