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Sep 13, 2023

Given an integer n and an integer array rounds. We have a circular track which consists of n sectors labeled from 1 to n. A marathon will be held on this track, the marathon consists of m rounds. The ith round starts at sector rounds[i - 1] and ends at sector rounds[i]. For example, round 1 starts at sector rounds[0] and ends at sector rounds[1]

Return an array of the most visited sectors sorted in ascending order.

Notice that you circulate the track in ascending order of sector numbers in the counter-clockwise direction (See the first example).

 

Example 1:

Input: n = 4, rounds = [1,3,1,2]
Output: [1,2]
Explanation: The marathon starts at sector 1. The order of the visited sectors is as follows:
1 --> 2 --> 3 (end of round 1) --> 4 --> 1 (end of round 2) --> 2 (end of round 3 and the marathon)
We can see that both sectors 1 and 2 are visited twice and they are the most visited sectors. Sectors 3 and 4 are visited only once.

Example 2:

Input: n = 2, rounds = [2,1,2,1,2,1,2,1,2]
Output: [2]

Example 3:

Input: n = 7, rounds = [1,3,5,7]
Output: [1,2,3,4,5,6,7]

 

Constraints:

  • 2 <= n <= 100
  • 1 <= m <= 100
  • rounds.length == m + 1
  • 1 <= rounds[i] <= n
  • rounds[i] != rounds[i + 1] for 0 <= i < m

Related Topics:
Array

Solution 1.

// OJ: https://leetcode.com/problems/most-visited-sector-in-a-circular-track/
// Author: github.com/lzl124631x
// Time: O(NM)
// Space: O(N)
class Solution {
public:
    vector<int> mostVisited(int n, vector<int>& A) {
        vector<int> cnt(n + 1);
        int i = A[0], mx = 1;
        cnt[i] = 1;
        for (int j = 1; j < A.size(); ++j) {
            while (i != A[j]) {
                if (++i == n + 1) i = 1;
                mx = max(mx, ++cnt[i]);
            }
        }
        vector<int> ans;
        for (int j = 1; j <= n; ++j) {
            if (cnt[j] == mx) ans.push_back(j);
        }
        return ans;
    }
};

Solution 2.

// OJ: https://leetcode.com/problems/most-visited-sector-in-a-circular-track/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(1)
// Ref: https://leetcode.com/problems/most-visited-sector-in-a-circular-track/discuss/806814/JavaC%2B%2BPython-From-Start-to-End
class Solution {
public:
    vector<int> mostVisited(int n, vector<int>& A) {
        vector<int> ans;
        if (A[0] <= A.back()) {
            for (int i = A[0]; i <= A.back(); ++i) ans.push_back(i);
        } else {
            for (int i = 1; i <= A.back(); ++i) ans.push_back(i);
            for (int i = A[0]; i <= n; ++i) ans.push_back(i);
        }
        return ans;
    }
};