1344

1344. Angle Between Hands of a Clock (Medium)

Given two numbers, hour and minutes. Return the smaller angle (in sexagesimal units) formed between the hour and the minute hand.

 

Example 1:

Input: hour = 12, minutes = 30
Output: 165

Example 2:

Input: hour = 3, minutes = 30
Output: 75

Example 3:

Input: hour = 3, minutes = 15
Output: 7.5

Example 4:

Input: hour = 4, minutes = 50
Output: 155

Example 5:

Input: hour = 12, minutes = 0
Output: 0

 

Constraints:

• 1 <= hour <= 12
• 0 <= minutes <= 59
• Answers within 10^-5 of the actual value will be accepted as correct.

Related Topics:
Math

Solution 1.

// OJ: https://leetcode.com/problems/angle-between-hands-of-a-clock/
// Author: github.com/lzl124631x
// Time: O(1)
// Space: O(1)
class Solution {
public:
    double angleClock(int h, int m) {
        double a = h * 30 + m * 0.5, b = m * 6, d = abs(a - b);
        return min(d, 360 - d);
    }
};