Given the root
of a binary tree, return its maximum depth.
A binary tree's maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Example 1:
Input: root = [3,9,20,null,null,15,7] Output: 3
Example 2:
Input: root = [1,null,2] Output: 2
Constraints:
- The number of nodes in the tree is in the range
[0, 104]
. -100 <= Node.val <= 100
Companies:
LinkedIn, Amazon, Google, Spotify, Microsoft
Related Topics:
Tree, Depth-First Search, Breadth-First Search, Binary Tree
Similar Questions:
- Balanced Binary Tree (Easy)
- Minimum Depth of Binary Tree (Easy)
- Maximum Depth of N-ary Tree (Easy)
- Time Needed to Inform All Employees (Medium)
// OJ: https://leetcode.com/problems/maximum-depth-of-binary-tree/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(N)
class Solution {
public:
int maxDepth(TreeNode* root) {
return root ? 1 + max(maxDepth(root->left), maxDepth(root->right)) : 0;
}
};