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给定一个整数数组 nums ,找到一个具有最大和的连续子数组(子数组最少包含一个元素),返回其最大和。
示例 1:
输入:nums = [-2,1,-3,4,-1,2,1,-5,4] 输出:6 解释:连续子数组 [4,-1,2,1] 的和最大,为 6 。
示例 2:
输入:nums = [1] 输出:1
示例 3:
输入:nums = [0] 输出:0
示例 4:
输入:nums = [-1] 输出:-1
示例 5:
输入:nums = [-100000] 输出:-100000
提示:
进阶:如果你已经实现复杂度为 O(n) 的解法,尝试使用更为精妙的 分治法 求解。
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/maximum-subarray 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
const maxSubArray = nums => { let sum = nums[0], max = nums[0] for (let i = 1; i < nums.length; i++) { const num = nums[i] if (sum > 0) { sum += num } else { sum = num } max = Math.max(sum, max) } return max }
The text was updated successfully, but these errors were encountered:
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给定一个整数数组 nums ,找到一个具有最大和的连续子数组(子数组最少包含一个元素),返回其最大和。
示例 1:
示例 2:
示例 3:
示例 4:
示例 5:
提示:
进阶:如果你已经实现复杂度为 O(n) 的解法,尝试使用更为精妙的 分治法 求解。
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/maximum-subarray
著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
The text was updated successfully, but these errors were encountered: