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567.go
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/
567.go
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package p567
/**
Given two strings s1 and s2, write a function to return true if s2 contains
the permutation of s1. In other words, one of the first string's permutations
is the substring of the second string.
Example 1:
Input:s1 = "ab" s2 = "eidbaooo"
Output:True
Explanation: s2 contains one permutation of s1 ("ba").
Example 2:
Input:s1= "ab" s2 = "eidboaoo"
Output: False
*/
// two pointer
func checkInclusion(s1 string, s2 string) bool {
charCnt := make([]int, 26)
for i := 0; i < len(s1); i++ {
charCnt[s1[i]-'a']++
}
cnt := len(s1)
i, j := 0, 0
for j < len(s2) {
c := s2[j] - 'a'
if charCnt[c] > 0 {
charCnt[c]--
cnt--
if cnt == 0 {
break
}
} else {
ic := s2[i] - 'a'
for ic != c {
charCnt[ic]++
cnt++
i++
ic = s2[i] - 'a'
}
i++
}
j++
}
return cnt == 0
}