-
Notifications
You must be signed in to change notification settings - Fork 0
/
063.go
55 lines (48 loc) · 1.09 KB
/
063.go
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
package p063
/**
Follow up for "Unique Paths":
Now consider if some obstacles are added to the grids.
How many unique paths would there be?
An obstacle and empty space is marked as 1 and 0 respectively in the grid.
For example,
There is one obstacle in the middle of a 3x3 grid as illustrated below.
[
[0,0,0],
[0,1,0],
[0,0,0]
]
The total number of unique paths is 2.
*/
func uniquePathsWithObstacles(obstacleGrid [][]int) int {
m := len(obstacleGrid)
if m == 0 {
return 0
}
n := len(obstacleGrid[0])
obstacleGrid[0][0] = 1 - obstacleGrid[0][0]
if obstacleGrid[0][0] == 0 {
return 0
}
for j := 1; j < n; j++ {
if obstacleGrid[0][j] != 1 {
obstacleGrid[0][j] = obstacleGrid[0][j-1]
} else {
obstacleGrid[0][j] = 0
}
}
for i := 1; i < m; i++ {
if obstacleGrid[i][0] != 1 {
obstacleGrid[i][0] = obstacleGrid[i-1][0]
} else {
obstacleGrid[i][0] = 0
}
for j := 1; j < n; j++ {
if obstacleGrid[i][j] != 1 {
obstacleGrid[i][j] = obstacleGrid[i][j-1] + obstacleGrid[i-1][j]
} else {
obstacleGrid[i][j] = 0
}
}
}
return obstacleGrid[m-1][n-1]
}