Division_16bit_8bit.txt

section .data
    prompt1 db 'Enter the 16-bit dividend (in decimal): ', 0
    prompt2 db 'Enter the 8-bit divisor (in decimal): ', 0
    result_msg db 'Quotient: ', 0
    result_msg2 db 'Remainder: ', 0
    newline db 10, 0   ; Newline character for formatting

section .bss
    dividend resw 1      ; 16-bit dividend
    divisor resb 1       ; 8-bit divisor
    quotient resw 1      ; 16-bit quotient
    remainder resb 1     ; 8-bit remainder

section .text
    global _start

_start:
    ; Display the prompt and read the 16-bit dividend
    mov eax, 4
    mov ebx, 1
    mov ecx, prompt1
    mov edx, 38
    int 0x80

    mov eax, 3
    mov ebx, 0
    mov ecx, dividend
    mov edx, 5
    int 0x80

    ; Display the prompt and read the 8-bit divisor
    mov eax, 4
    mov ebx, 1
    mov ecx, prompt2
    mov edx, 35
    int 0x80

    mov eax, 3
    mov ebx, 0
    mov ecx, divisor
    mov edx, 2
    int 0x80

    ; Load the dividend and divisor from memory
    mov ax, [dividend]
    mov al, [divisor]

    ; Clear quotient and remainder registers
    xor dx, dx
    xor bx, bx

    ; Perform division
    div bl

    ; Store the quotient and remainder in memory
    mov [quotient], ax
    mov [remainder], dl

    ; Display the result (quotient)
    mov eax, 4
    mov ebx, 1
    mov ecx, result_msg
    mov edx, 9
    int 0x80

    mov eax, 4
    mov ebx, 1
    mov ecx, quotient
    mov edx, 5
    int 0x80

    ; Display the result (remainder)
    mov eax, 4
    mov ebx, 1
    mov ecx, result_msg2
    mov edx, 11
    int 0x80

    mov eax, 4
    mov ebx, 1
    mov ecx, remainder
    mov edx, 2
    int 0x80

    ; Exit the program
    mov eax, 1
    mov ebx, 0
    int 0x80