Create ruby2.py

added union and intersection in python

Author: rubybano

ruby2.py

@@ -0,0 +1,49 @@
+# Python program to find union and intersection
+# using sets
+
+
+def printUnion(arr1, arr2, n1, n2):
+	hs = set()
+
+	# Insert the elements of arr1[] to set hs
+	for i in range(0, n1):
+		hs.add(arr1[i])
+
+	# Insert the elements of arr1[] to set hs
+	for i in range(0, n2):
+		hs.add(arr2[i])
+	print("Union:")
+	for i in hs:
+		print(i, end=" ")
+	print("\n")
+
+	# Prints intersection of arr1[0..n1-1] and
+	# arr2[0..n2-1]
+
+
+def printIntersection(arr1, arr2, n1, n2):
+	hs = set()
+
+	# Insert the elements of arr1[] to set S
+	for i in range(0, n1):
+		hs.add(arr1[i])
+	print("Intersection:")
+	for i in range(0, n2):
+
+		# If element is present in set then
+		# push it to vector V
+		if arr2[i] in hs:
+			print(arr2[i], end=" ")
+
+
+# Driver Program
+arr1 = [7, 1, 5, 2, 3, 6]
+arr2 = [3, 8, 6, 20, 7]
+n1 = len(arr1)
+n2 = len(arr2)
+
+# Function call
+printUnion(arr1, arr2, n1, n2)
+printIntersection(arr1, arr2, n1, n2)
+
+# This artice is contributed by Kumar Suman .