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add 344-zeze1004
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solutions/344/344-zeze1004(1).py

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class Solution:
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def reverseString(self, s: List[str]) -> None:
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"""
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Do not return anything, modify s in-place instead.
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"""
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s[:] = s[::-1]

solutions/344/344-zeze1004.cpp

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#include <string>
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#include <algorithm>
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class Solution
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{
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public:
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void reverseString(vector<char> &s)
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{
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vector<char> str;
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for (int i = s.size() - 1; i >= 0; i--)
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{
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char word = s[i];
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str.push_back(word);
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}
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s.erase(s.begin(), s.end());
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for (int i = 0; i < str.size(); i++)
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{
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char word = str[i];
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s.push_back(word);
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}
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}
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};

solutions/344/344-zeze1004.md

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# 443. Fizz Buzz
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## solution 1
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시간복잡도 : O(1)
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알고리즘 : 구현
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풀이 설명 : list s를 슬라이싱하여 문자열을 역순으로 저장한다.
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소스코드 : [link](<./344-zeze1004(1).py>)

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