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66. Plus One.py
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66. Plus One.py
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"""
https://leetcode.com/problems/plus-one/
You are given a large integer represented as an integer array digits, where each digits[i] is
the ith digit of the integer. The digits are ordered from most significant to least significant
in left-to-right order. The large integer does not contain any leading 0's.
Increment the large integer by one and return the resulting array of digits.
Example 1:
Input: digits = [1,2,3]
Output: [1,2,4]
Explanation: The array represents the integer 123.
Incrementing by one gives 123 + 1 = 124.
Thus, the result should be [1,2,4].
Example 2:
Input: digits = [4,3,2,1]
Output: [4,3,2,2]
Explanation: The array represents the integer 4321.
Incrementing by one gives 4321 + 1 = 4322.
Thus, the result should be [4,3,2,2].
Example 3:
Input: digits = [9]
Output: [1,0]
Explanation: The array represents the integer 9.
Incrementing by one gives 9 + 1 = 10.
Thus, the result should be [1,0].
"""
class Solution(object):
def plusOne(self, digits: list):
"""
:type digits: List[int]
:rtype: List[int]
Time: O(n)
Space: O(1)
"""
for i in range(len(digits) - 1, -1, -1):
if digits[i] == 9:
digits[i] = 0
else:
digits[i] += 1
return digits
return [1] + digits
solution = Solution()
assert solution.plusOne([1, 2, 3]) == [1, 2, 4]
assert solution.plusOne([4, 3, 2, 1]) == [4, 3, 2, 2]
assert solution.plusOne([9]) == [1, 0]
assert solution.plusOne([9, 9]) == [1, 0, 0]
assert solution.plusOne([1]) == [2]