/**
Problem Name : Search a 2D Matrix
Problem URL : https://leetcode.com/problems/search-a-2d-matrix/
Description :
Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
Integers in each row are sorted from left to right.
The first integer of each row is greater than the last integer of the previous row.
Difficulty : Medium
Language : C++
Category : Algorithms - Data Structures - 2D Arrays
*/
class Solution
{
public:
bool searchMatrix(vector<vector<int>>& matrix, int target)
{
int n = matrix.size();
int m = matrix[0].size();
int s = 0;
int e = n * m - 1;
while(s <= e)
{
int mid = (s + e)/2;
int i = mid / m;
int j = mid % m;
if (matrix[i][j] == target)
return true;
else if (matrix[i][j] < target)
s = mid + 1;
else
e = mid - 1;
}
return false;
}
};