/**
Problem URL : https://leetcode.com/problems/symmetric-tree/
Description :
Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).
Difficulty : Easy
Language : C#
Category : Algorithms - trees
*/
/* Definition for a binary tree node at the end. */
public class Solution
{
public bool IsSymmetric(TreeNode root)
{
if(root == null)
return true;
return RecursiveIsSymmetricUtill(root.left, root.right);
}
private bool RecursiveIsSymmetricUtill(TreeNode left, TreeNode right)
{
if(left == null && right == null)
return true;
if(left == null && right != null)
return false;
if(left != null && right == null)
return false;
if(left.val != right.val)
return false;
if(!RecursiveIsSymmetricUtill(left.left, right.right) || !RecursiveIsSymmetricUtill(left.right, right.left))
return false;
return true;
}
}
/**
* Definition for a binary tree node.
* public class TreeNode {
* public int val;
* public TreeNode left;
* public TreeNode right;
* public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/