给你一个嵌套的整数列表 nestedList
。每个元素要么是一个整数,要么是一个列表;该列表的元素也可能是整数或者是其他列表。请你实现一个迭代器将其扁平化,使之能够遍历这个列表中的所有整数。
实现扁平迭代器类 NestedIterator
:
NestedIterator(List<NestedInteger> nestedList)
用嵌套列表nestedList
初始化迭代器。int next()
返回嵌套列表的下一个整数。boolean hasNext()
如果仍然存在待迭代的整数,返回true
;否则,返回false
。
你的代码将会用下述伪代码检测:
initialize iterator with nestedList res = [] while iterator.hasNext() append iterator.next() to the end of res return res
如果 res
与预期的扁平化列表匹配,那么你的代码将会被判为正确。
示例 1:
输入:nestedList = [[1,1],2,[1,1]]
输出:[1,1,2,1,1]
解释:通过重复调用 next 直到 hasNext 返回 false,next 返回的元素的顺序应该是: [1,1,2,1,1]
。
示例 2:
输入:nestedList = [1,[4,[6]]]
输出:[1,4,6]
解释:通过重复调用 next 直到 hasNext 返回 false,next 返回的元素的顺序应该是: [1,4,6]
。
提示:
1 <= nestedList.length <= 500
- 嵌套列表中的整数值在范围
[-106, 106]
内
# """
# This is the interface that allows for creating nested lists.
# You should not implement it, or speculate about its implementation
# """
#class NestedInteger:
# def isInteger(self) -> bool:
# """
# @return True if this NestedInteger holds a single integer, rather than a nested list.
# """
#
# def getInteger(self) -> int:
# """
# @return the single integer that this NestedInteger holds, if it holds a single integer
# Return None if this NestedInteger holds a nested list
# """
#
# def getList(self) -> [NestedInteger]:
# """
# @return the nested list that this NestedInteger holds, if it holds a nested list
# Return None if this NestedInteger holds a single integer
# """
class NestedIterator:
def __init__(self, nestedList: [NestedInteger]):
def dfs(nestedList):
for e in nestedList:
if e.isInteger():
self.vals.append(e.getInteger())
else:
dfs(e.getList())
self.vals = []
dfs(nestedList)
self.cur = 0
def next(self) -> int:
res = self.vals[self.cur]
self.cur += 1
return res
def hasNext(self) -> bool:
return self.cur < len(self.vals)
# Your NestedIterator object will be instantiated and called as such:
# i, v = NestedIterator(nestedList), []
# while i.hasNext(): v.append(i.next())
/**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* public interface NestedInteger {
*
* // @return true if this NestedInteger holds a single integer, rather than a nested list.
* public boolean isInteger();
*
* // @return the single integer that this NestedInteger holds, if it holds a single integer
* // Return null if this NestedInteger holds a nested list
* public Integer getInteger();
*
* // @return the nested list that this NestedInteger holds, if it holds a nested list
* // Return null if this NestedInteger holds a single integer
* public List<NestedInteger> getList();
* }
*/
public class NestedIterator implements Iterator<Integer> {
private List<Integer> vals;
private Iterator<Integer> cur;
public NestedIterator(List<NestedInteger> nestedList) {
vals = new ArrayList<>();
dfs(nestedList);
cur = vals.iterator();
}
@Override
public Integer next() {
return cur.next();
}
@Override
public boolean hasNext() {
return cur.hasNext();
}
private void dfs(List<NestedInteger> nestedList) {
for (NestedInteger e : nestedList) {
if (e.isInteger()) {
vals.add(e.getInteger());
} else {
dfs(e.getList());
}
}
}
}
/**
* Your NestedIterator object will be instantiated and called as such:
* NestedIterator i = new NestedIterator(nestedList);
* while (i.hasNext()) v[f()] = i.next();
*/