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is_a does not work with NamedIndividuals #77

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bbartley opened this issue May 17, 2023 · 0 comments
Open

is_a does not work with NamedIndividuals #77

bbartley opened this issue May 17, 2023 · 0 comments

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@bbartley
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is_a can be used to infer that one term is a subclass of another term. However, it does not currently support inferring that a NamedIndividual is an instance of a class.
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@bbartley