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2269-find-the-k-beauty-of-a-number/README.md

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+<h2><a href="https://leetcode.com/problems/find-the-k-beauty-of-a-number/">2269. Find the K-Beauty of a Number</a></h2><h3>Easy</h3><hr><div><p>The <strong>k-beauty</strong> of an integer <code>num</code> is defined as the number of <strong>substrings</strong> of <code>num</code> when it is read as a string that meet the following conditions:</p>
+
+<ul>
+	<li>It has a length of <code>k</code>.</li>
+	<li>It is a divisor of <code>num</code>.</li>
+</ul>
+
+<p>Given integers <code>num</code> and <code>k</code>, return <em>the k-beauty of </em><code>num</code>.</p>
+
+<p>Note:</p>
+
+<ul>
+	<li><strong>Leading zeros</strong> are allowed.</li>
+	<li><code>0</code> is not a divisor of any value.</li>
+</ul>
+
+<p>A <strong>substring</strong> is a contiguous sequence of characters in a string.</p>
+
+<p>&nbsp;</p>
+<p><strong>Example 1:</strong></p>
+
+<pre><strong>Input:</strong> num = 240, k = 2
+<strong>Output:</strong> 2
+<strong>Explanation:</strong> The following are the substrings of num of length k:
+- "24" from "<strong><u>24</u></strong>0": 24 is a divisor of 240.
+- "40" from "2<u><strong>40</strong></u>": 40 is a divisor of 240.
+Therefore, the k-beauty is 2.
+</pre>
+
+<p><strong>Example 2:</strong></p>
+
+<pre><strong>Input:</strong> num = 430043, k = 2
+<strong>Output:</strong> 2
+<strong>Explanation:</strong> The following are the substrings of num of length k:
+- "43" from "<u><strong>43</strong></u>0043": 43 is a divisor of 430043.
+- "30" from "4<u><strong>30</strong></u>043": 30 is not a divisor of 430043.
+- "00" from "43<u><strong>00</strong></u>43": 0 is not a divisor of 430043.
+- "04" from "430<u><strong>04</strong></u>3": 4 is not a divisor of 430043.
+- "43" from "4300<u><strong>43</strong></u>": 43 is a divisor of 430043.
+Therefore, the k-beauty is 2.
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>1 &lt;= num &lt;= 10<sup>9</sup></code></li>
+	<li><code>1 &lt;= k &lt;= num.length</code> (taking <code>num</code> as a string)</li>
+</ul>
+</div>