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0002.两数相加.java
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/*
* @lc app=leetcode.cn id=2 lang=java
*
* [2] 两数相加
*
* https://leetcode-cn.com/problems/add-two-numbers/description/
*
* algorithms
* Medium (36.08%)
* Likes: 3625
* Dislikes: 0
* Total Accepted: 285.7K
* Total Submissions: 788.5K
* Testcase Example: '[2,4,3]\n[5,6,4]'
*
* 给出两个 非空 的链表用来表示两个非负的整数。其中,它们各自的位数是按照 逆序 的方式存储的,并且它们的每个节点只能存储 一位 数字。
*
* 如果,我们将这两个数相加起来,则会返回一个新的链表来表示它们的和。
*
* 您可以假设除了数字 0 之外,这两个数都不会以 0 开头。
*
* 示例:
*
* 输入:(2 -> 4 -> 3) + (5 -> 6 -> 4)
* 输出:7 -> 0 -> 8
* 原因:342 + 465 = 807
*
*
*/
// @lc code=start
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class Solution {
/*
public class ListNode {
int val;
ListNode next;
ListNode(int x) { val = x; }
}
*/
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
ListNode tmp = new ListNode(0);
ListNode curr = tmp;
int carry = 0;
while (l1 != null || l2 != null) {
int x = (l1 != null) ? l1.val : 0;
int y = (l2 != null) ? l2.val : 0;
int sum = carry + x + y;
carry = sum / 10;
curr.next = new ListNode(sum % 10);
curr = curr.next;
if (l1 != null) {
l1 = l1.next;
}
if (l2 != null) {
l2 = l2.next;
}
}
if (carry == 1) {
curr.next = new ListNode(carry);
}
return tmp.next;
}
}
// @lc code=end