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Copy path15. 3Sum.cpp
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15. 3Sum.cpp
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/*
Given an array nums of n integers, are there elements a, b, c in nums such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.
Note:
The solution set must not contain duplicate triplets.
Example:
Given array nums = [-1, 0, 1, 2, -1, -4],
A solution set is:
[
[-1, 0, 1],
[-1, -1, 2]
]
Sort first, then do comparison, early break, etc..
*/
class Solution {
public:
vector<vector<int>> threeSum(vector<int>& nums) {
sort( nums.begin(), nums.end() );
vector<vector<int>> res;
if ( nums.empty() || nums.front() > 0 || nums.back() < 0 ) return res;
for ( int i = 0; i <= (int)nums.size() - 3; ++i )
{
if ( nums[i] > 0 ) break;
if ( i > 0 && nums[i] == nums[i - 1] ) continue;
int target = -nums[i];
int j = i + 1, k = nums.size() - 1;
while ( j < k )
{
if ( nums[j] + nums[k] == target )
{
res.push_back( {nums[i], nums[j], nums[k]} );
while ( j < k && nums[j + 1] == nums[j] ) ++j;
while ( j < k && nums[k - 1] == nums[k] ) --k;
++j;
--k;
}
else if ( nums[j] + nums[k] < target )
++j;
else
--k;
}
}
return res;
}
};