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Ideally, I would like to be able to do
x = Map({'a': 2, 'c': 1})
y = x.update({'b': 3: 'c': 2)
z = y - x # magic
z == Map({'b': 3, 'c': 2})
Is there any particularly efficient way to do this in terms of memory and computational time? Ideally, I'd like z
to share its data with y
in the same way y
shares its data with x
. One way that comes to mind is
def diff(y, x):
z = y
for k, v in y.items():
if k in x and x[k] == v:
z = z.delete('k')
return z
But this is O(N log N) (for log N get/set). Is there a more efficient way to go about this?
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