A more efficient way is to use a circular queue. Specifically, we may use a fixed-size array and two pointers to indicate the starting position and the ending position. And the goal is to reuse the wasted storage we mentioned previously.
class MyCircularQueue {
private:
vector<int> data;
int head;
int tail;
int size;
public:
/** Initialize your data structure here. Set the size of the queue to be k. */
MyCircularQueue(int k) {
data.resize(k);
head = -1;
tail = -1;
size = k;
}
/** Insert an element into the circular queue. Return true if the operation is successful. */
bool enQueue(int value) {
if (isFull()) {
return false;
}
if (isEmpty()) {
head = 0;
}
tail = (tail + 1) % size;
data[tail] = value;
return true;
}
/** Delete an element from the circular queue. Return true if the operation is successful. */
bool deQueue() {
if (isEmpty()) {
return false;
}
if (head == tail) {
head = -1;
tail = -1;
return true;
}
head = (head + 1) % size;
return true;
}
/** Get the front item from the queue. */
int Front() {
if (isEmpty()) {
return -1;
}
return data[head];
}
/** Get the last item from the queue. */
int Rear() {
if (isEmpty()) {
return -1;
}
return data[tail];
}
/** Checks whether the circular queue is empty or not. */
bool isEmpty() {
return head == -1;
}
/** Checks whether the circular queue is full or not. */
bool isFull() {
return ((tail + 1) % size) == head;
}
};