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This repository has been archived by the owner on May 11, 2021. It is now read-only.
If BC is parallel to AE and have the same length (The correct answer to the question) then AB is parallel and has the same length as CE. So CE has a length of 5. The triangle CDE can't exist because of the Pythagorean theorem. If the angle of D is 90 degrees (as shown) then CD²+DE²=CE². In this case it's 2²+4²=5². To solve this issue, correct the length of CD to 3.
Sincerely,
Eddy
The text was updated successfully, but these errors were encountered:
Hi,
Reporting an error in one of the questions.
Reference exercise: matrix_dimensions.
If BC is parallel to AE and have the same length (The correct answer to the question) then AB is parallel and has the same length as CE. So CE has a length of 5. The triangle CDE can't exist because of the Pythagorean theorem. If the angle of D is 90 degrees (as shown) then CD²+DE²=CE². In this case it's 2²+4²=5². To solve this issue, correct the length of CD to 3.
Sincerely,
Eddy
The text was updated successfully, but these errors were encountered: