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longest-increasing-subsequence solution
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/**
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* @param {number[]} nums
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* @return {number}
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*/
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var lengthOfLIS = function(nums) {
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const dp = new Array(nums.length).fill(1);
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for (let i = 0; i < nums.length; i++) {
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for (let j = 0; j < i; j++) {
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if (nums[j] < nums[i] && dp[j] >= dp[i]) {
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dp[i] = dp[j] + 1;
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}
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}
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}
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return Math.max(...dp);
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};
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// 시간 복잡도 : O(n^2)
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// 공간 복잡도 : O(n)

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