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Copy path168_ExcelSheetColumnTitle.py
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168_ExcelSheetColumnTitle.py
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# https://leetcode.com/problems/excel-sheet-column-title/
# 2022年04月17日 12:30:02
class Solution(object):
def convertToTitle(self, columnNumber):
"""
:type columnNumber: int
:rtype: str
"""
# # v1 iterative, handleing Z problem separately
# ret=[]
# while columnNumber>0:
# if columnNumber%26==0: # deal with 'Z'
# ret.append('Z')
# columnNumber=columnNumber/26-1
# else:
# ret.append(chr(ord('A')-1+columnNumber%26))
# columnNumber=(columnNumber-columnNumber%26)/26
# return ''.join(ret[::-1])
# v1.1
# ret=[]
# while columnNumber>0:
# if columnNumber%26!=0:
# thisord=columnNumber%26
# else:
# thisord=26
# ret.append(chr(ord('A')-1+thisord))
# columnNumber=(columnNumber-thisord)/26
# return ''.join(ret[::-1])
# # v1.2 using a new variable to handle the 'Z' problem
# ret=[]
# while columnNumber>0:
# thisord=columnNumber%26 if columnNumber%26!=0 else 26
# ret.append(chr(ord('A')-1+thisord))
# columnNumber=(columnNumber-thisord)/26
# return ''.join(ret[::-1])
# v2 copied oneliner
return "" if columnNumber == 0 else self.convertToTitle((columnNumber - 1) / 26) + chr((columnNumber - 1) % 26 + ord('A'))