forked from keon/algorithms
-
Notifications
You must be signed in to change notification settings - Fork 0
/
minimum_spanning_tree.py
130 lines (109 loc) · 4.21 KB
/
minimum_spanning_tree.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
# Minimum spanning tree (MST) is going to use an undirected graph
#
# The disjoint set is represented with an list <n> of integers where
# <n[i]> is the parent of the node at position <i>.
# If <n[i]> = <i>, <i> it's a root, or a head, of a set
class Edge:
def __init__(self, u, v, weight):
self.u = u
self.v = v
self.weight = weight
class DisjointSet:
def __init__(self, n):
# Args:
# n (int): Number of vertices in the graph
self.parent = [None] * n # Contains wich node is the parent of the node at poisition <i>
self.size = [1] * n # Contains size of node at index <i>, used to optimize merge
for i in range(n):
self.parent[i] = i # Make all nodes his own parent, creating n sets.
def merge_set(self, a, b):
# Args:
# a, b (int): Indexes of nodes whose sets will be merged.
# Get the set of nodes at position <a> and <b>
# If <a> and <b> are the roots, this will be constant O(1)
a = self.findSet(a)
b = self.findSet(b)
# Join the shortest node to the longest, minimizing tree size (faster find)
if self.size[a] < self.size[b]:
self.parent[a] = b # Merge set(a) and set(b)
self.size[b] += self.size[a] # Add size of old set(a) to set(b)
else:
self.parent[b] = a # Merge set(b) and set(a)
self.size[a] += self.size[b] # Add size of old set(b) to set(a)
def find_set(self, a):
if self.parent[a] != a:
# Very important, memoize result of the
# recursion in the list to optimize next
# calls and make this operation practically constant, O(1)
self.parent[a] = self.find_set(self.parent[a])
# node <a> it's the set root, so we can return that index
return self.parent[a]
def kruskal(n, edges, ds):
# Args:
# n (int): Number of vertices in the graph
# edges (list of Edge): Edges of the graph
# ds (DisjointSet): DisjointSet of the vertices
# Returns:
# int: sum of weights of the minnimum spanning tree
#
# Kruskal algorithm:
# This algorithm will find the optimal graph with less edges and less
# total weight to connect all vertices (MST), the MST will always contain
# n-1 edges because it's the minimum required to connect n vertices.
#
# Procedure:
# Sort the edges (criteria: less weight).
# Only take edges of nodes in different sets.
# If we take a edge, we need to merge the sets to discard these.
# After repeat this until select n-1 edges, we will have the complete MST.
edges.sort(key=lambda edge: edge.weight)
mst = [] # List of edges taken, minimum spanning tree
for edge in edges:
set_u = ds.findSet(edge.u) # Set of the node <u>
set_v = ds.findSet(edge.v) # Set of the node <v>
if set_u != set_v:
ds.merge_set(set_u, set_v)
mst.append(edge)
if len(mst) == n-1:
# If we have selected n-1 edges, all the other
# edges will be discarted, so, we can stop here
break
return sum([edge.weight for edge in mst])
if __name__ == "__main__":
# Test. How input works:
# Input consists of different weighted, connected, undirected graphs.
# line 1:
# integers n, m
# lines 2..m+2:
# edge with the format -> node index u, node index v, integer weight
#
# Samples of input:
#
# 5 6
# 1 2 3
# 1 3 8
# 2 4 5
# 3 4 2
# 3 5 4
# 4 5 6
#
# 3 3
# 2 1 20
# 3 1 20
# 2 3 100
#
# Sum of weights of the optimal paths:
# 14, 40
import sys
for n_m in sys.stdin:
n, m = map(int, n_m.split())
ds = DisjointSet(m)
edges = [None] * m # Create list of size <m>
# Read <m> edges from input
for i in range(m):
u, v, weight = map(int, input().split())
u -= 1 # Convert from 1-indexed to 0-indexed
v -= 1 # Convert from 1-indexed to 0-indexed
edges[i] = Edge(u, v, weight)
# After finish input and graph creation, use Kruskal algorithm for MST:
print("MST weights sum:", kruskal(n, edges, ds))