diff --git a/html/notebooks/nmodl-kinetic-schemes.html b/html/notebooks/nmodl-kinetic-schemes.html index 257def2df0..52bcf6c4fb 100644 --- a/html/notebooks/nmodl-kinetic-schemes.html +++ b/html/notebooks/nmodl-kinetic-schemes.html @@ -149,7 +149,7 @@

Law of Mass Action

\frac{dY_j}{dt} = \sum_i \Delta \nu_{ij} r_i

-

where \Delta \nu_{ij} = \nu_{ij}^R - \nu_{ij}^L, and

+

where \Delta \nu_{ij} = \nu_{ij}^R - \nu_{ij}^L, and

r_i = k_i \prod_j Y_j^{\nu_{ij}^R}

@@ -162,7 +162,7 @@

KINETIC block formatwhere - A0 etc are the species A_j - the integer preceeding a species (with or without a space) is the corresponding stochiometric coefficient \nu_{ij} (implicitly 1 if not specified) - kf is the forwards reaction rate k^{(f)}_j - kb is the backwards reaction rate k^{(b)}_j, i.e. the reaction rate for the same reaction with the LHS and RHS exchanged *** We can convert these statements to a system of ODEs using the law of Mass Action:

\frac{dY_j}{dt} = \sum_i \Delta \nu_{ij} (r^{(f)}_i - r^{(b)}_i)

-

where \Delta \nu_{ij} = \nu_{ij}^R - \nu_{ij}^L, and

+

where \Delta \nu_{ij} = \nu_{ij}^R - \nu_{ij}^L, and

\begin{aligned}
 r^{(f)}_i &= k^{(f)}_i \prod_j Y_j^{\nu_{ij}^{L}} \\
diff --git a/html/notebooks/nmodl-odes-overview.html b/html/notebooks/nmodl-odes-overview.html
index 4747db0dba..d7388e8dfd 100644
--- a/html/notebooks/nmodl-odes-overview.html
+++ b/html/notebooks/nmodl-odes-overview.html
@@ -203,7 +203,7 @@ <h2><code class=NONLINEAR

  • construct F(X), with Jacobian J(X)=\frac{\partial F_i}{\partial X_j}

  • such that desired solution X^* satisfies condition F(X^*) = 0

  • -
  • iterative solution given by X_{n+1} = X_n + J(X_n)^{-1} F(X_n)

  • +
  • iterative solution given by X_{n+1} = X_n + J(X_n)^{-1} F(X_n)

  • see the nmodl-nonlinear-solver notebook for more details ***

  • diff --git a/html/notebooks/nmodl-sympy-solver-cnexp.html b/html/notebooks/nmodl-sympy-solver-cnexp.html index d366e586da..346832a5ea 100644 --- a/html/notebooks/nmodl-sympy-solver-cnexp.html +++ b/html/notebooks/nmodl-sympy-solver-cnexp.html @@ -345,7 +345,15 @@

    Ex. 4

    -exact solution:      m = minf+(m-minf)*exp(dt/mtau)
    +exact solution:
    +
    + +
    +
    +
    +
    +
    +     m = minf+(m-minf)*exp(dt/mtau)