WhatsappApiException not expose the status code

[pcomp96]

Hi @Bindambc,

I resumed developing the integration I was implementing, while I was wrapping the CRUD API of the whatsapp media files to expose them to the integrating system, I noticed that the WhatsappApiException class has the WhatsappApiError object as a private member. It does not have a method that returns the status code of the checked exception. Being a REST call, it would need a getStatusCode method at least to return the status code occurred in the call.

The API I'm testing is the retrieveMediaUrl by mediaId.

When I call the API with an ID that doesn't exist I would like to return 404 from my API but I have no way to discriminate that

Using a provider, In this case, i catch the exception but i have to return 500 because i don't have the status code.

The exception I get is the following.

Would it be expensive to add a statusCode return?

Waiting for your reply, I hope I was helpful.

Thank you,
Giuseppe

[Bindambc]

Hello @pcomp96 ,

I can modify the class WhatsappApiException by adding a method called getWhatsappApiError() that will allow obtaining the error object. Within the error object, you will be able to check the error codes sent by WhatsApp API.

Could this help you?

[Bindambc]

@pcomp96
I could also return the HTTP code, but I'm not sure if it would be helpful. Note that in the case of media not found, the HTTP code is 400.

[pcomp96]

Sorry for the late reply @Bindambc,

I can modify the class WhatsappApiException by adding a method called getWhatsappApiError() that will allow obtaining the error object. Within the error object, you will be able to check the error codes sent by WhatsApp API.

Yes is perfect because the class WhatsappApiException return only the message of the exception throwed from API.

I could also return the HTTP code, but I'm not sure if it would be helpful. Note that in the case of media not found, the HTTP code is 400.

I think that is the best way to register the HTTP status code in the WhatsappApiError and expose it with public int getHttpStatusCode().

I hope that is useful 😀.

Thanks,
Giuseppe.