Merge pull request #63 from Suxxxxhyun/Suxxxxhyun

[Solved] PRG_크기가 작은 부분 문자열

Author: Suxxxxhyun

Week2/공통/크기가_작은_부분문자열/suhyun.java

@@ -0,0 +1,21 @@
+package Week2.공통.크기가_작은_부분문자열;
+
+public class suhyun {
+    public static int solution(String t, String p) {
+        int answer = 0;
+        for(int i=0; i<t.length() - p.length() + 1; i++){
+            String s = "";
+            s = t.substring(i, i+p.length());
+            if(Long.parseLong(s) <= Long.parseLong(p)){
+                answer += 1;
+            }
+        }
+        return answer;
+    }
+
+    public static void main(String[] args){
+        String t = "3141592";
+        String p = "271";
+        System.out.println(solution(t, p));
+    }
+}

Week2/공통/크기가_작은_부분문자열/suhyun.py

@@ -0,0 +1,13 @@
+def solution(t, p):
+    answer = 0
+    for idx in range(0, len(t) - len(p) + 1):
+        s = ""
+        for i in range(idx, idx + len(p)):
+            s += t[i]
+        if int(s) <= int(p):
+            answer += 1
+    return answer
+
+t = "3141592"
+p = "271"
+print(solution(t, p))

Week2/공통/크기가_작은_부분문자열/suhyun1.py

@@ -0,0 +1,12 @@
+def solution(t, p):
+    answer = 0
+    for idx in range(0, len(t) - len(p) + 1):
+        s = ""
+        s = t[idx:idx+len(p)]
+        if int(s) <= int(p):
+            answer += 1
+    return answer
+
+t = "3141592"
+p = "271"
+print(solution(t, p))